(2x+3)(x^2+x-2)=0

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Solution for (2x+3)(x^2+x-2)=0 equation: 


Simplifying
(2x + 3)(x2 + x + -2) = 0

Reorder the terms:
(3 + 2x)(x2 + x + -2) = 0

Reorder the terms:
(3 + 2x)(-2 + x + x2) = 0

Multiply (3 + 2x) * (-2 + x + x2)
(3(-2 + x + x2) + 2x * (-2 + x + x2)) = 0
((-2 * 3 + x * 3 + x2 * 3) + 2x * (-2 + x + x2)) = 0
((-6 + 3x + 3x2) + 2x * (-2 + x + x2)) = 0
(-6 + 3x + 3x2 + (-2 * 2x + x * 2x + x2 * 2x)) = 0
(-6 + 3x + 3x2 + (-4x + 2x2 + 2x3)) = 0

Reorder the terms:
(-6 + 3x + -4x + 3x2 + 2x2 + 2x3) = 0

Combine like terms: 3x + -4x = -1x
(-6 + -1x + 3x2 + 2x2 + 2x3) = 0

Combine like terms: 3x2 + 2x2 = 5x2
(-6 + -1x + 5x2 + 2x3) = 0

Solving
-6 + -1x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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